What is the maximum number of values that can be stored with 3 bits?

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Multiple Choice

What is the maximum number of values that can be stored with 3 bits?

Explanation:
The maximum number of values that can be stored with a certain number of bits is determined by the formula \(2^n\), where \(n\) is the number of bits. In this case, with 3 bits, you would calculate \(2^3\). When you perform the calculation, you find that \(2^3 = 8\). This means that with 3 bits, you can represent a total of 8 unique combinations or values. Each bit can have a value of either 0 or 1, and with three bits, the combinations are as follows: - 000 - 001 - 010 - 011 - 100 - 101 - 110 - 111 These combinations represent the decimal values 0 through 7, confirming that a maximum of 8 distinct values can indeed be stored using 3 bits.

The maximum number of values that can be stored with a certain number of bits is determined by the formula (2^n), where (n) is the number of bits. In this case, with 3 bits, you would calculate (2^3).

When you perform the calculation, you find that (2^3 = 8). This means that with 3 bits, you can represent a total of 8 unique combinations or values. Each bit can have a value of either 0 or 1, and with three bits, the combinations are as follows:

  • 000

  • 001

  • 010

  • 011

  • 100

  • 101

  • 110

  • 111

These combinations represent the decimal values 0 through 7, confirming that a maximum of 8 distinct values can indeed be stored using 3 bits.

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